Question

find four solutions (x,y)for the polynomials y=x²-4x​

Answer 1

Step-by-step explanation:

Fist solution

x= 0

y=x^2-4x

y=(0)^2-4(0)

y=0-0

y=0

Second x= 1

Y=(1)^2-4(1)

y=1-4

y=-3

Third x= 2

y=(2)^2-4(2)

y=4-8

y=-4

Fourth x=-2

y=(-2)^2-4(-2)

y=4-(-4)

y=8

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