Question

Find four terms in AP whose sum is 50 and in which the greatest number is 4 times the least

Answer 1

Step-by-step explanation:

let the 4 number be a - 3d , a - d , a + d , a +3 d

then a - 3d +a - d + a + d + a + 3d=50

4a=50

a=25/2

but a + 3d = 4(a-3d)

a + 3d = 4a - 12d

3a=15d

a=5d

25/2=5d

d=5/2

so the 4 no's are

a-3d=25/2-15/2=10/2=5

a-d=25/2-5/2=20/2=10

a+d= 25/2+5/2=15

a+3d= 25/2+15/2=20

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