Question

find g(31415927)

def g(x):
(q,d) = (1,0)
while q <= x:
(q,d) = (q*10,d+1)
return(d)

Answer 1

Answer is 25

While the loop will run 25 times

As 31415927 / 2**24 =1.8...  which is > 1

So for last time it will go  

For 2**25 , d will be incremented 24+1=25  

Then it becomes less than 1

Condition becomes false... while loop terminates

-->the no. of times x is divided by 2 & remains >1

The d will be incremented by 1.

Answer 2

Given:

g(31415927)

( q, d ) = ( 1, 0 )

Condition:  

q <= x

Then,

( q , d ) = ( q * 10, d + 1 )

Solution:

The loop returns a value if q > 31415927

When d = 8,

The value of q = 100000000 and so q > 31415927

Hence,  the function returns 8.

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