Question

Find G.F.I at point A deu to B,C

Answer 1

Answer:

Given:

10 kg and 20 kg mass is present at vertices of a traingle . Let sides of triangle be "a"

To find:

Gravitational Field Intensity at point A due to Point B and Point C

Formulas used:

Gravitational Field Intensity at a distance "r" is given as :

$GFI \: = \frac{Gm}{ {r}^{2} }$

Now, we should consider direction as it is a vector.

Calculation:

Field intensity at A due to Point B

$= \frac{G \times 10}{ {a}^{2} }$

Field intensity at A due to Point C

$= \frac{G \times 20}{ {a}^{2} }$

Then perform Vector addition to get the net Gravitational Field Intensity : For tge Calculation, look at the photo.

Final answer is

$\boxed{ \boxed{GFI \: net = \frac{10G}{ {a}^{2} } \sqrt{7} }}$