Find [g(x) ifa P(x) = x³ - 7x²+16.q(x)x²-2x+3 and r(x)=3x-2
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Answer:
Given polynomial,
2x³+7x²−24x−45
We have to prove that x−3 is a factor of the given polynomial.
x−3=0
x=3
Put x=3,
=2(3)
3
+7(3)
2
−24(3)−45
=2(27)+7(9)−72−45
=54+63−72−45
=117−117
=0
As the remainder is 0,x−3 is a factor of the given polynomial.
Hence proved
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