find g(x),ig p(x)=x²+5x+13 wheb q(x(=(x+2) and r(x)=7
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Answer :-
Given :-
- p(x) = x² + 5x + 13
- q(x) = x + 2
- r(x) = 7
To Find :-
- g(x)
Solution :-
We know that,
→ p(x) = g(x) × q(x) + r(x)
Substituting the values in formula :-
→ x² + 5x + 13 = ( x + 2 ) × g(x) + 7
→ x² + 5x + 13 - 7 = ( x + 2 ) × g(x)
→ x² + 5x + 6 = ( x + 2 ) × g(x)
→ x² + 2x + 3x + 6 = ( x + 2 ) × g(x)
→ x ( x + 2 ) + 3 ( x + 2 ) = ( x + 2 ) × g(x)
→ ( x + 3 ) ( x + 2 ) = ( x + 2 ) × g(x)
→ ( x + 3 ) ( x + 2 ) / ( x + 2 ) = g(x)
→ g(x) = x + 3
Value of g(x) = x + 3
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