Question

find general and middle term in the expansion of (a-b)^12​

Answer 1

✏ Answer :

general term

$t(12) =t(11 + 1) = (n)c(r) \times a {}^{n - r} \times -b {}^{r} \\ = 12c11 \times a {}^{12 - 11} \times -b {}^{11} \\ = 12c11 \times a {}^{1} \times -b {}^{11}$

Answer 2

Hey mate here is your answer ❤️....