find general solution for tan theta = -1/root 3
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Given : Tan θ = - 1/√3
To find : general solution for θ
Solution:
Tan θ = - 1/√3
=> θ = Tan⁻¹ ( - 1/√3)
Principal Range of Tan⁻¹ is ( -π/2 , π/2)
& Tan(-π/6) = - 1/√3
=> θ = -π/6
Generalized Solution θ = nπ -π/6
Learn more:
What is the principal value of cos -¹[cos 2pi/3] + sin-¹[cos 2pi/3]?
https://brainly.in/question/17532985
Write the principal value of tan-¹(-1). - Brainly.in
https://brainly.in/question/17533155
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Answer:
tan theta equals to 180
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