Question

Find general solution for te following:

1, sec^2 2x =1- tan2x
2, sinx +sin3x +sin5x =0.

Answer 1

I hope this is correct and if it helped you please mark it brainliest

Answer 2

1).
${( \sec(2x) )}^{2} = 1 - \tan(2x)$
${( \sec(2x) )}^{2} - 1 = - \tan(2x)$
${( \tan(2x)) }^{2} = - \tan(2x)$
$\tan(2x) ( \tan(2x) - 1) = 0$
$\tan(2x) = 0 \: \: or \: \: \tan(2x) +1 = 0$
or 2x=0 or 2x=π/2+π/4
or x=0. or x=3π/8