Question

find general solution of ....... 5tan⁴x-sec⁴x = 29​

Answer 1

Step-by-step explanation:

5tan⁴x- sec⁴x=29

(5tan²x)²- (sec²x)²=29

now the formula of a²-b²=(a+b).(a-b)

(5tan²x+sec²x).(5tan²x-sec²x)=29

(5tan²x+1+tan²x).(5tan²x-1-tan²x)=29

(6tan²x+1).(4tan²x-1)=29

sorry aage aap solve Kar lo

Answer 2

Answer:

to the power 4 ko 2 hole square karke solve karo