Math, asked by abhayyadav178811, 6 months ago

find general solution of x^4y^iv+6x^3y^"'+2x^2y^"-4xy^'+4y=6x^3sinx by using variation of parameters

Answers

Answered by TanpraNaymay

1

Answer:

hegwiwbevwiwkbwvwowbevsidhe

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