find general solution:
sec^2 2x = 1-tan2x
Answers
Answered by
3
Answer:
Step-by-step explanation:
sec
2
2x=1−tan2x
1+tan
2
2x=1−tan2x
tan
2
2x+tan2x=0
tan2x(tan2x+1)=0
tan2x=0 or tan2x+1=0
Now, tan2x=0
tan2x=tan0
2x=nπ+0,n∈Z
x=
2
nπ
,n∈Z
tan2x+1=0
tan2x=−1=−tan
4
π
=tan(π−
4
π
)=tan
4
3π
2x=nπ+
4
3π
,n∈Z
x=
2
nπ
+
8
3π
,n∈Z
Therefore, the general solution is
2
nπ
or
2
nπ
+
8
3π
,n∈Z
Trust me it is correct
I am math teacher
Please give me thanks and brainlist
It motivates me
Answered by
1
Step-by-step explanation:
good afternoon have a great day
Attachments:
Similar questions