Math, asked by chhaauhann, 1 month ago

find general solution:
sec^2 2x = 1-tan2x

Answers

Answered by sharmamonika925
3

Answer:

Step-by-step explanation:

sec  

2

2x=1−tan2x

1+tan  

2

2x=1−tan2x

tan  

2

2x+tan2x=0

tan2x(tan2x+1)=0

tan2x=0 or tan2x+1=0

Now, tan2x=0

tan2x=tan0

2x=nπ+0,n∈Z

x=  

2

,n∈Z

tan2x+1=0

tan2x=−1=−tan  

4

π

=tan(π−  

4

π

)=tan  

4

 

2x=nπ+  

4

,n∈Z

x=  

2

+  

8

,n∈Z

Therefore, the general solution is  

2

 or  

2

+  

8

,n∈Z

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Answered by kavitha2057
1

Step-by-step explanation:

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