Question

find general term in expansion of (x^2-1/x)^12​

Answer 1

Answer:

Hope will help...!!

Step-by-step explanation:

General term in (a+b)n is given by,

Tr+1=C(n,r)an−rbr

So, in given expression,

(x2−y)6)

Tr+1=C(6,r)(x2)6−r(−y)r

Tr+1=(−1)r⋅C(6,r)(x)12−2r(y)r