Math, asked by chinmaybhatia9, 13 days ago

Find geometrically the value of sin45°​

Answers

Answered by Daksh3105
1

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Answered by kartikesingh977
0

in triangle ABC

proof in angle ABC

∠A+∠B+∠C=180°

45°+90°+∠C=180°

∠C=45°

∠A=∠C=45°

find AC using phythagoras theorem

AC²=AB²+BC²⇒AC²=x²+x²⇒AC²=2x²⇒AC=√2x

sinA=BC/AC  ⇒x*/√2x⇒1/√2

∠A+∠C=45°

sin 45°=1/√2

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