Find geometrically the value of sin45°
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in triangle ABC
proof in angle ABC
∠A+∠B+∠C=180°
45°+90°+∠C=180°
∠C=45°
∠A=∠C=45°
find AC using phythagoras theorem
AC²=AB²+BC²⇒AC²=x²+x²⇒AC²=2x²⇒AC=√2x
sinA=BC/AC ⇒x*/√2x⇒1/√2
∠A+∠C=45°
sin 45°=1/√2
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