find gof and fog f(x)=x^2+3 and g(x)=x^3-1
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Answer:
f(x)=x²+3
g(x)=x³-1
fog=
f(g(x))=
f(x³-1)=
(x³-1)²+3=
x⁶+1-2x³+3=
x⁶-2x³+4
gof=
g(f(x))=
g(x²+3)=
(x²+3)³-1=
x⁶+27+3(x²)(3)²+3(x²)²(3)-1=
x⁶+27+27x²+9x⁴-1=
x⁶+9x⁴+27x²+26=0
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