Question

find GP for which sum of first two term is 3 while fifth term is four times the third term

Answer 1

Answer:

where a= first term

r= common ratio

Answer 2

GP would be $1,2,4,8......$

Step-by-step explanation:

Since we have given that

Sum of first two terms = 3

So, mathematically, it is expressed as

$a+ar=3\\\\a(1+r)=3$-----------------------(1)

fifth term is 4 times the third term.

So, it becomes,

$a_5=4a_3\\\\ar^4=4ar^2\\\\r^2=4\\\\r=\sqrt{4}\\\\r=2$

Put the value of r in eq(1), we get that

$a(1+r)=3\\\\a(1+2)=3\\\\a\times 3=3\\\\a=1$

So, GP would be $1,2,4,8......$

# learn more:

In a gp the sum of the first two terms is -4 and the fifth term is four times the third term . Find the gp

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