find graphically the vertics of the triangle whose side have the equation 2y - x = 8, 5y - x= 14 and 2x-y =-1
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2y - x = 8
2y = 8 + x
y = 8 + x / 2
Sub x = 0
y = 8 + 0 / 2
y = 4
5y - x = 14
5y = 14 + x
y = 14 + x / 5
Sub x = 1
y = 14 + 1 / 5
y = 3
2x - y = 1
2x = 1 + y
x = 1 + y / 2
Sub y = 1
x = 1 + 1 / 2
x = 2
Therefore, the vertices of the triangle are (0,4) ; (1,3) ; (1,2).
2y = 8 + x
y = 8 + x / 2
Sub x = 0
y = 8 + 0 / 2
y = 4
5y - x = 14
5y = 14 + x
y = 14 + x / 5
Sub x = 1
y = 14 + 1 / 5
y = 3
2x - y = 1
2x = 1 + y
x = 1 + y / 2
Sub y = 1
x = 1 + 1 / 2
x = 2
Therefore, the vertices of the triangle are (0,4) ; (1,3) ; (1,2).
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