find greater no. that will divide 410,751,1030 leaving the rem. 7m in each case
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410-7=403
751-7=744
1030-7=1023
Now,
403=31×13
744=2×2×2×31
1023=3×11×31
∴,The greatest no. that will divide 410,751,1030 is 31.
751-7=744
1030-7=1023
Now,
403=31×13
744=2×2×2×31
1023=3×11×31
∴,The greatest no. that will divide 410,751,1030 is 31.
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