Math, asked by bapunkumarnath095, 7 months ago

find greatest 4digit number which is divisible by 10,15,21,and 28

Answers

Answered by nizamsaqib0

0

Answer:

the answer is

10 -2.5

15-3.75

21 - 5.25

28 - 7

the greatest 28-7

Answered by MrBrock

1

Answer:

9660

Step-by-step explanation:

First we need to take LCM of 10,15,21 and 28 that is 420

Now the greatest 4 digit number is 9999 when divided by 420 leaves remainder 339

Thus our greatest 4 digit number divisible by 10,15,21 and 28 will be 9999- 339 = 9660

Previous Question

Next Question

Similar questions

Math, 3 months ago

15. Manish bought 1000 pencils for 3000 and sold 200 of these at a gain of 5%. At what gain per cent he must sell the remaining pencils so as to gain 15 % on the whole transaction...

Biology, 3 months ago

describe main features of archaea...

Math, 3 months ago

2. Ray found the perimeter of the window in his bedroom to be 12 feet. If the length of the window is 4 feet long, what is the width?

Math, 7 months ago

if √5 = 2.23 and √7 = 2.64 then correct to one decimal place the value of 1/√7-√5...

Chemistry, 7 months ago

what do u mean by colligative properties ?

Physics, 11 months ago

Parallel combination of resistance is the current of 7.5 ampere from 30 volt battery with two of the resistance resistance of 10 ohm and 12 ohm find the resistance of third resistor...

Math, 11 months ago

5 pencil and 7 pens together cost rupees 50 ,whereas7 pencils and 5 pens together cost rupees 46. Find the cost of one pencil and that of one pen solve it...

Chemistry, 11 months ago

Oxidising agent and reducing agent of copper oxide react with water to form copper and water...