Math, asked by bapunkumarnath095, 7 months ago

find greatest 4digit number which is divisible by 10,15,21,and 28​

Answers

Answered by nizamsaqib0
0

Answer:

the answer is

10 -2.5

15-3.75

21 - 5.25

28 - 7

the greatest 28-7

Answered by MrBrock
1

Answer:

9660

Step-by-step explanation:

First we need to take LCM of 10,15,21 and 28 that is 420

Now the greatest 4 digit number is 9999 when divided by 420 leaves remainder 339

Thus our greatest 4 digit number divisible by 10,15,21 and 28 will be 9999- 339 = 9660

Similar questions