Question

Find H.C.F of 1405 and 1465 by Euclid’s division algorithm.​

Answer 1

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Step-by-step explanation:

Find HCF of no.s 1405,1465,1530 by euclids division

hi bro

hi bro use this method to derive your answer

hi bro use this method to derive your answerHere 1530 > 1465

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 65

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5 Here 1405 > 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5 Here 1405 > 51405 = 5 × 281 + 0

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5 Here 1405 > 51405 = 5 × 281 + 0HCF(1405, 5)= 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5 Here 1405 > 51405 = 5 × 281 + 0HCF(1405, 5)= 5

hi bro use this method to derive your answerHere 1530 > 14651530 = 1465 × 1 + 651465 = 65 × 22 + 35 65 = 35 × 1 + 30 35 = 30 × 1 + 5 30 = 5 × 6 + 0 HCF(1465, 1530) = 5 Here 1405 > 51405 = 5 × 281 + 0HCF(1405, 5)= 5 Therefore HCF(1405,1465,1530)= 5

Answer 2

Answer:

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