Question

find H. C. F Of 453&297 step by step l will mark as brainlest​

Answer 1

Answer:

Step 1: Since 453 > 297, we apply the division lemma to 453 and 297, to get

453 = 297 x 1 + 156

Step 2: Since the reminder 297 ≠ 0, we apply division lemma to 156 and 297, to get

297 = 156 x 1 + 141

Step 3: We consider the new divisor 156 and the new remainder 141, and apply the division lemma to get

156 = 141 x 1 + 15

We consider the new divisor 141 and the new remainder 15,and apply the division lemma to get

141 = 15 x 9 + 6

We consider the new divisor 15 and the new remainder 6,and apply the division lemma to get

15 = 6 x 2 + 3

We consider the new divisor 6 and the new remainder 3,and apply the division lemma to get

6 = 3 x 2 + 0

The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 3, the HCF of 297 and 453 is 3

Step-by-step explanation: