Question

find H.C.F.OF 60, 12, 36

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Answer 1

Answer:

$60 \: hcf$

The highest common factor is found by multiplying all the factors which appear in both lists: So the HCF of 60 and 72 is 2 × 2 × 3 which is 12. The lowest common multiple is found by multiplying all the factors which appear in either list: So the LCM of 60 and 72 is 2 × 2 × 2 × 3 × 3 × 5 which is 360.

$12 \: hcf$

Factors of 12 = 1, 2, 3, 4, 6 and 12. Factors of 18 = 1, 2, 3, 6, 9 and 18. Therefore, common factor of 12 and 18 = 1, 2, 3 and 6. Highest common factor (H.C.F) of 12 and 18 = 6 [since 6 is the highest common factor].

$36 \: hcf$

Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18 and 36. Therefore, common factor of 24 and 36 = 1, 2, 3, 4, 6, 8 and 12. Highest common factor (H.C.F) of 24 and 36 = 12.

Answer 2

SOLUTION

TO DETERMINE

The HCF of 60 , 12 , 36

CONCEPT TO BE IMPLEMENTED

HCF :

For the given two or more numbers HCF is the greatest number that divides each of the numbers

LCM :

For the given two or more numbers LCM is the least number which is exactly divisible by each of the given numbers

EVALUATION

Here the given numbers are 60 , 12 , 36

We prime factorise the given numbers

60 = 2 × 2 × 3 × 5

12 = 2 × 2 × 3

36 = 2 × 2 × 3 × 3

Hence the required HCF

= 2 × 2 × 3

= 12

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