find had of 104 25 65 by Euclid division lemma
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Answer:
4
Step-by-step explanation:
a=bq+r(a=104,b=25)
104=25×4+4
25=4×6+1
4=1×4+0
HCF of 104&25=4
a=bq+r(a=65,b=4)
65=4×16+1
4=1×4+0
HCF of 4&65=4
HCF of 104,25&65=4
nehasain:
are yar thanks for answering but you have to use division lemma
not hcf method
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