Question

find half-life time of a first order reaction with rate constant k = 2.31 X 10^-14 s^-1

Answer 1

Answer: The half life time of the first order reaction is $3\times 10^{13}s$

Explanation:

To calculate the half life of the first order reaction, we use the equation:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the first order reaction

k = rate constant of the reaction = $2.31\times 10^{-14}s^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{2.31\times 10^{-14}s^{-1}}=0.3\times 10^{14}s=3\times 10^{13}s$

Hence, the half life time of the first order reaction is $3\times 10^{13}s$

Answer 2

Answer:k=2.31*10-14s-1

T1/2=0.693/k

0.3*10-14s-1

Explanation: