Math, asked by binamahato17, 9 months ago

Find HCF and LCM by using the property in Question no. 1.
(a) 27, 90
(b) 145, 232
(c) 117, 221​

Answers

Answered by arnavs0223
62

1.

The HCF of 27 and 90 is 9.

Steps to find GCF

Find the prime factorization of 27

27 = 3 × 3 × 3

Find the prime factorization of 90

90 = 2 × 3 × 3 × 5

To find the HCF, multiply all the prime factors common to both numbers:

Therefore, HCF = 3 × 3

GCF = 9

The lcm of 27 and 90 is 270.

Steps to find LCM

Find the prime factorization of 27

27 = 3 × 3 × 3

Find the prime factorization of 90

90 = 2 × 3 × 3 × 5

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:

LCM = 2 × 3 × 3 × 3 × 5

LCM = 270

2.

The gcf of 145 and 232 is 29.

Steps to find GCF

Find the prime factorization of 145

145 = 5 × 29

Find the prime factorization of 232

232 = 2 × 2 × 2 × 29

To find the gcf, multiply all the prime factors common to both numbers:

Therefore, GCF = 29

he lcm of 145 and 232 is 1160.

Steps to find LCM

Find the prime factorization of 145

145 = 5 × 29

Find the prime factorization of 232

232 = 2 × 2 × 2 × 29

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:

LCM = 2 × 2 × 2 × 5 × 29

LCM = 1160

3.

The gcf of 117 and 221 is 13.

Steps to find GCF

Find the prime factorization of 117

117 = 3 × 3 × 13

Find the prime factorization of 221

221 = 13 × 17

To find the gcf, multiply all the prime factors common to both numbers:

Therefore, GCF = 13

Find the prime factorization of 117

117 = 3 × 3 × 13

Find the prime factorization of 221

221 = 13 × 17

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the lcm:

LCM = 3 × 3 × 13 × 17

LCM = 1989

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Answered by AryaNayak54321
48

Answer:

HCF OF ( 27 , 90 ) IS 6

LCM OF ( 27 , 90 ) IS 270

HCF OF ( 145 , 132 ) IS 29

LCM OF ( 145 , 232 ) IS 1160

HCF OF ( 117 , 221 ) IS 13

LCM OF ( 117 , 221 ) IS 1989

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