find HCF and LCM of 12 14 45
Answers
Answered by
24
12=2×2×3
45=3×3×5
75=3×5×2
HCF=2
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Answered by
11
Answer:
Given 3 numbers 12, 45 and 75
we have to find the HCF of above 3 numbers
we will find the HCF by prime factorization method
The factors are
12 = 2 x 2 x 3
45 = 3 x 3 x 5
75 = 3 x 5 x 5
The highest common factor from the above these factors is 3
Hence, HCF 12,45,75=3
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