find HCF and LCM of 12 15 and 21 by prime factorization method
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12=2×2×3
15=3×5
21=3×7
common factor = 3
HCF=3
LCM=2×2×3×5×7
=420
15=3×5
21=3×7
common factor = 3
HCF=3
LCM=2×2×3×5×7
=420
hcf=2
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HCF of two numbers is 23 and their LCM is 1549 one of the number is 161 then find other number
bhai 1449 hai not 1549
bro equation de raha hoon solve tu kar le
Euclid algorithm to find the HCF of 4052 and 12576
1449×23=161×othernumber
who enjoys the power matlab given in the concurrent list in India
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answer is above....,,..,..,..........
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