find hcf and lcm of 144,96,54 by prime factorization
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Answer:
Using the factor tree for the prime factorisation of 144, 96 and 54, we have
\(144=16\times 9=2^4\times3^2\)
\(96=32\times 3=2^5\times 3^1\)
\(54=2\times 27=2^1\times 3^3\)
To find the HCF, we list the common factors and their least exponents in 144, 96 and 54 as follows:
\(\therefore\) HCF of 144, 96 and 54 \(=2^1\times 3^1=6\)
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Step-by-step explanation:
144=2×2×2×2×3×3=2^4×3^2
96=2×2×2×2×2×3=2^5×3
54=2×3×3×3=2×3^3
HCF=2×3=6
LCM=2^5×3^3=32×27=864
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