find hcf and lcm of 404 and 96 and verify that hcf ×lcm = product of the two given no
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HCF of 404 and 96
404 = 2*2*101
96 = 2*2*2*2*2*3
Common Factors = 2*2
HCF of 404 and 96 = 4
LCM of 404 and 96
404 = 2*2*101
96 = 2*2*2*2*2*3
LCM = 2*2*2*2*2*3*101 = 9696
LCM of 404 and 96 is 9696
HCF × LCM = Product of the two numbers
⇒ 4*9696 = 404*96
⇒ 38784 = 38784
LHS = RHS
Hence, it is verified.
Hope it will help you ☺️
404 = 2*2*101
96 = 2*2*2*2*2*3
Common Factors = 2*2
HCF of 404 and 96 = 4
LCM of 404 and 96
404 = 2*2*101
96 = 2*2*2*2*2*3
LCM = 2*2*2*2*2*3*101 = 9696
LCM of 404 and 96 is 9696
HCF × LCM = Product of the two numbers
⇒ 4*9696 = 404*96
⇒ 38784 = 38784
LHS = RHS
Hence, it is verified.
Hope it will help you ☺️
quest2:
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