find hcf and lcm of 56 and 112 by prime factorization method
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Answered by
33
Hey!
Here is your answer!
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56=2×2×2×7
112=2×2×2×2×7
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HCF=2×2×2×7=56
LCM=2×2×2×2×7=112
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So, the HCF and LCM of 56 and 112 are 56 and 112 respectively.
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Hope it's satisfactory!
Here is your answer!
_____________________________
56=2×2×2×7
112=2×2×2×2×7
_____________________________
HCF=2×2×2×7=56
LCM=2×2×2×2×7=112
_____________________________
So, the HCF and LCM of 56 and 112 are 56 and 112 respectively.
_____________________________
Hope it's satisfactory!
Answered by
17
Thanks for the question.
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