find HCF and LCM of 6,72,120give fast
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Answered by
10
Hey!!!!!
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By Prime Factorisation Method
=> 6 = 2 x 3
=> 72 = 2³ x 3²
=> 120 = 2³ x 3 x 5
Thus
=> HCF(6,72,120) = 2 x 3
=> HCF(6,72,120)= 6
Similarly
=> LCM(6,72,120) = 2³ x 3² x 5
=> LCM(6,72,120) = 8 x 9 x 5
=> LCM = 360
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Hope this helps ✌️
__________
By Prime Factorisation Method
=> 6 = 2 x 3
=> 72 = 2³ x 3²
=> 120 = 2³ x 3 x 5
Thus
=> HCF(6,72,120) = 2 x 3
=> HCF(6,72,120)= 6
Similarly
=> LCM(6,72,120) = 2³ x 3² x 5
=> LCM(6,72,120) = 8 x 9 x 5
=> LCM = 360
__________
Hope this helps ✌️
Answered by
8
The answer is given below :
The given numbers are 6, 72 and 120.
By prime factorization method, we find
6 = 2 × 3
72 = 2 × 2 × 2 × 3 × 3
120 = 2 × 2 × 2 × 3 × 5
HCF = HIGHEST COMMON FACTOR,
i.e., the common factors of all the three numbers
So, required HCF
= 2 × 3
= 6
LCM = LEAST COMMON MULTIPLE,
i.e., the number multipled by all the three numbers
So, required LCM
= 2 × 3 × 2 × 2 × 3 × 5
= 360
Thank you for your question.
The given numbers are 6, 72 and 120.
By prime factorization method, we find
6 = 2 × 3
72 = 2 × 2 × 2 × 3 × 3
120 = 2 × 2 × 2 × 3 × 5
HCF = HIGHEST COMMON FACTOR,
i.e., the common factors of all the three numbers
So, required HCF
= 2 × 3
= 6
LCM = LEAST COMMON MULTIPLE,
i.e., the number multipled by all the three numbers
So, required LCM
= 2 × 3 × 2 × 2 × 3 × 5
= 360
Thank you for your question.
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