Question

find HCF and LCM of 6 ,72 and 120 using fundamental theorem of arithmetic​

Answer 1

Answer:

Here we have :-

6 = 2 × 3

72 => 2 × 2 × 2 × 3 × 3 = 2³ × 3²

120 => 2 × 2 × 2 × 3 × 5 = 2³ × 3¹ × 5¹

HCF(6,72,120) => 2¹ × 3¹ = 6

LCM(6,72,120) => 2³ × 3² × 5¹ = 360

explanation:Pls mark as brainliest

Answer 2

Answer:

Given:

1 st number = 6

2 nd number = 72

3 rd number = 120

SOLUTION:

$fundamental \: theorem \: of \: arithmetic \: tells \\ that \: every \: composite \: number \: can \: be \: \\ expressed \: in \: the \: product \: of \: prime. \\ \\ \: 6 = 2 \times 3 \times 1 \\ \\ 72 = 2 \times 2 \times 2 \times 3 \times 3 \times 1\\ \\ 120 = 2 \times 2 \times 2 \times 3 \times 5 \times 1\\ \\ hcf \: = 2 \times 3 \times 1 \\ \\ \: \: \: \: = \: \: \: \: 6 \\ \\ lcm \: = \: 2 \times 2 \times 2 \times 3 \times 3 \times 5 \\ \\ \: \: \: \: \: \: \: \: \: \: = 360$

you can verify

LCM*HCF = PRODUCT OF TWO NUMBER.