Math, asked by sagarsinha5682, 5 months ago

Find HCF and LCM of (a)18,48 (b)30,42

Answers

Answered by Anonymous
8

Answer:

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Step-by-step explanation:

  1. Numbers=18,48.

=>18=2*3*3

=2*3^2

=>48=2*2*2*2*3

=2^4*3.

As HCF it the product of the lowest power of each common factor.

So HCF(18,48)=2*3

=6.

As LCM is the product of the highest power of each factor.

So LCM(18,48)=2*2*2*2*3*3

=2^4*3^3

=16*9

=144.

2. Numbers=30,42

=>30=2*3*5

=>42=2*3*7

So HCF(30,42)=2*3

=6.

And LCM(30,42)=2*3*5*7

=14*15

=210.

So the HCF&LCM of (18,48) are 6 and 144 respectively and the HCF&LCM of (30,42) are 6 and 210 respectively.

HOPE IT HELPS.

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