Find HCF and LCM of (a)18,48 (b)30,42
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Answer:
Step-by-step explanation:
- Numbers=18,48.
=>18=2*3*3
=2*3^2
=>48=2*2*2*2*3
=2^4*3.
☆As HCF it the product of the lowest power of each common factor.
So HCF(18,48)=2*3
=6.
☆As LCM is the product of the highest power of each factor.
So LCM(18,48)=2*2*2*2*3*3
=2^4*3^3
=16*9
=144.
2. Numbers=30,42
=>30=2*3*5
=>42=2*3*7
So HCF(30,42)=2*3
=6.
And LCM(30,42)=2*3*5*7
=14*15
=210.
☞So the HCF&LCM of (18,48) are 6 and 144 respectively and the HCF&LCM of (30,42) are 6 and 210 respectively.
HOPE IT HELPS.
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