Math, asked by jaswinderkaur121976, 9 months ago

Find HCF and LCM of
(iii) 8,9 and 25​

Answers

Answered by Anonymous
7

Answer:

8 = 2 \times 2 \times 2   \\  \\ 9 = 3 \times 3 \\  \\ 25 = 5 \times 5 \\  \\ h.c.f = 1 \\  \\ l.c.m = 1800

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Answered by mohnishkrishna05
0

:

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Using prime factorisation method:

(i) 12, 15 and 21

Factor of 12=2×2×3

Factor of 15=3×5

Factor of 21=3×7

HCF (12,15,21)=3

LCM (12,15,21)=2×2×3×5×7=420

(ii) 17, 23 and 29

Factor of 17=1×17

Factor of 23=1×23

Factor of 29=1×29

HCF (17,23,29)=1

LCM (17,23,29)=1×17×23×29=11,339

(iii) 8, 9 and 25

Factor of 8=2×2×2×1

Factor of 9=3×3×1

Factor of 25=5×5×1

HCF (8,9,25)=1

LCM (8,9,25)=2×2×2×3×3×5×5=1,800

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