find HCF and LCM of the following given pairs of numbers by prime factorization method first 120, 90
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Hi,
________________________
1 ) HCF of numbers = Product of the
smallest power of each common
prime factors of the numbers.
2 ) LCM = Product of the greatest
power of each prime factors of the numbers.
__________________________
i ) 120, 90
Write the given numbers into product
of prime.
120 = 2 × 2 × 2 × 3 × 5
= 2³ × 3 × 5
90 = 2 × 3 × 3 × 5
= 2 × 3² × 5
HCF( 90, 120) = 2 × 3 × 5 = 30
LCM( 90 , 120 ) = 2³ × 3² × 5 = 360
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
________________________
1 ) HCF of numbers = Product of the
smallest power of each common
prime factors of the numbers.
2 ) LCM = Product of the greatest
power of each prime factors of the numbers.
__________________________
i ) 120, 90
Write the given numbers into product
of prime.
120 = 2 × 2 × 2 × 3 × 5
= 2³ × 3 × 5
90 = 2 × 3 × 3 × 5
= 2 × 3² × 5
HCF( 90, 120) = 2 × 3 × 5 = 30
LCM( 90 , 120 ) = 2³ × 3² × 5 = 360
☆ ☆ ☆ Hop its helpful ☆ ☆ ☆
☆ Regards :- ♡♡《 Nitish kr singh 》♡♡
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