Math, asked by blazeflitzz, 1 year ago

find HCF and LCM of the following integers by expressing them as product of primes and verify that LCM (a×b)=a×b

1) 16 and 80​

Answers

Answered by Anonymous
19

2l16

2l8

2l4

2

★ Prime factor of 16 = 2 × 2 × 2 × 2 = 2⁴

2l 80

2l 40

2l 20

2l10

5

★ Prime factor of 576 = 2 × 2 × 2 × 2 × 5 = 2⁴ × 5

Hence,

H.C.F ( 16,80 ) = 2⁴ = 16

L.C.M ( 426,576 ) = 2⁴ × 5 = 16 × 5 = 80

Verify:

L.C.M × H.C.F = Product of two numbers

⇒ 80 × 16 = 16 × 80

⇒ 1,280 = 1,280

Therefore, L.HS = R.HS

verified.

Answered by singh600
14

Answer:

here is answer mate....thxxx for brain list answer...

Step-by-step explanation:

lcm and hcf of 16 and 80 are 80 and 16...lcm=80 , hcf=16

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