Question

find hcf and lcm of (x²-1)(x³-1)and(x²-2x+1)​

Answer 1

Answer:

Step-by-step explanation:

x  

3

−1=(x−1)(x  

2

+x+1)

x  

4

+x  

2

+1=(x  

2

+x+1)(x  

2

−x+1)

Clearly H.C.F of x  

3

−1 and x  

4

+x  

2

+1

i.e.H.C.F of (x−1)(x  

2

+x+1) and (x  

2

+x+1)(x  

2

−x+1) is  (x  

2

+x+1)