Math, asked by saivengaden2, 30 days ago

find hcf and lcm of (x²-1)(x³-1)and(x²-2x+1) pls anyone answer this question this is the challenge for you​

Answers

Answered by chirag9090singh9090
0

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Factors of:

( {x}^{2}  - 1)( {x}^{3}  - 1)

 = ( {x}^{2}  -  {1}^{2} )( {x}^{3}  - 1)

 = (x + 1)(x - 1)( {x}^{3}  - 1 )

=> (x + 1), (x - 1) and (x³ - 1)

 {x}^{2}  - 2x + 1

 =  {(x)}^{2}  - 2(x)(1) +  {(1)}^{2}

 =  {(x - 1)}^{2}

=> x - 1

SO THE HCF IS :

x - 1

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