Question

Find hcf for the following by prime factorisattion
A)81 and 27
B)112and160
With explanation

Answer 1

Answer:

HCF of 81 and 27 is 27

HCF of 112 and 160 is 16

Step-by-step explanation:

Prime factorization of 81 = 3x3x3x3

Prime factorization of 27 = 3x3x3

HCF is the least no. of common factors

therefore, HCF(81,27)= 3x3x3 = 27

Prime factorization of 112= 2x2x2x2x7

Prime factorization of 160= 2x2x2x2x2x5

HCF(112,160)= 2x2x2x2= 16