find HCF of 1032 and 408
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By EDL
Here 1032> 408
1032 = 408×2 +216
408 = 216 × 1 +192
216 = 192 × 1 +24
192 = 24 × 8 +0
Here we get 0 so our procedure stops here.
So the HCF of 1032 and 408 is 24
Here 1032> 408
1032 = 408×2 +216
408 = 216 × 1 +192
216 = 192 × 1 +24
192 = 24 × 8 +0
Here we get 0 so our procedure stops here.
So the HCF of 1032 and 408 is 24
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