Find HCF of 107 &595, using Euclid's algorithm...
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Answer:
107
Step-by-step explanation:
595=(107×5)+60
107=(60×1)+47
60=(47×1)+13
47=(13×3)+8
13=(8×1)+5
8=(5×1)+3
5=(3×1)+2
3=(2×1)+1
1=(1×1)+0
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