Find hcf of 12, 15,and 21 using division algorithm
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HCF of 12, 15, 21 ==>
21 = 15 x 1 + 6
15 = 6 x 2 + 3
6 = 3 x 2 + 0
now,
15 = 12 x 1 + 3
12 = 3 x 4 + 0
HCF = 3
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prime factor of 12=2×2×3
prime factor of 15=3×5
prime factor of 21=3×7
lcm =420 ,hcf=3
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