find HCF of 12 and 108 and write its 10 X + 12 find X and Y
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Answer:
H.C.F = 12
and
x = 0 and y = 1
Explanation:
We are given
First number = 12
Second number = 108
we know that
Prime factorization of 12 = 2 × 2 × 3
Prime factorization of 108 = 2 × 2 × 3 × 3 × 3
Highest common factor = H.C.F = 2 × 2 × 3 = 12
And
IF we suppose
10x + 12y = 12
Then
It implies that
x = 0 and y = 1
that is
10(0) + 12(1) = 12
So
H.C.F = 12
and
x = 0 and y = 1
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