Question

find HCF of 12 and 108 and write its 10 X + 12 find X and Y​

Answer 1

Answer:

H.C.F = 12

and

x = 0 and y = 1

Explanation:

We are given

First number = 12

Second number = 108

we know that

Prime factorization of 12 = 2 × 2 × 3

Prime factorization of 108 = 2 × 2 × 3 × 3 × 3

Highest common factor = H.C.F = 2 × 2 × 3 = 12

And

IF we suppose

10x + 12y = 12

Then

It implies that

x = 0 and y = 1

that is

10(0) + 12(1) = 12

So

H.C.F = 12

and

x = 0 and y = 1