find HCF of 120 and 48 and Express it is in the form of 120 M + 488n
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Correct Question :
Find the HCF of 120 and 48 and Express it in the form of 120 M + 48 N.
AnsWer :
M = 1.
N = -2.
Solution :
Dividend = Divisor * Q + R.
Now,
120>48.
HCF of (120 , 48 ) = 24.
It's Expression,
Where, M = 1 and N = -2.
Therefore, the value of expression be M = 1 and N = -2.
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