find hcf of 1254 using listing multiples
Answers
Answer:
Factors of 1254 =1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254
Distinct Factors of 1254 = 1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254,
Note: Factors of 1254 and Distinct factors are the same.
Factors of -1254 = -1, -2, -3, -6, -11, -19, -22, -33, -38, -57, -66, -114, -209, -418, -627, -1254,
What are the Factors of 1257
Factors of 1257 =1, 3, 419, 1257
Distinct Factors of 1257 = 1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254, 1, 3, 419, 1257,
Note: Factors of 1257 and Distinct factors are the same.
Factors of -1257 = -1, -2, -3, -6, -11, -19, -22, -33, -38, -57, -66, -114, -209, -418, -627, -1254, -1, -3, -419, -1257,
Negative factors are just factors with negative sign.The factors are numbers that can divide 1257 without remainder.
Every number is divisible by itself and 1.
Factors of 1254
1254/1 = 1254 gives remainder 0 and so are divisible by 1
1254/2 = 627 gives remainder 0 and so are divisible by 2
1254/3 = 418 gives remainder 0 and so are divisible by 3
1254/6 = 209 gives remainder 0 and so are divisible by 6
1254/11 = 114 gives remainder 0 and so are divisible by 11
1254/19 = 66 gives remainder 0 and so are divisible by 19
1254/22 = 57 gives remainder 0 and so are divisible by 22
1254/33 = 38 gives remainder 0 and so are divisible by 33
1254/38 = 33 gives remainder 0 and so are divisible by 38
1254/57 = 22 gives remainder 0 and so are divisible by 57
1254/66 = 19 gives remainder 0 and so are divisible by 66
1254/114 = 11 gives remainder 0 and so are divisible by 114
1254/209 = 6 gives remainder 0 and so are divisible by 209
1254/418 = 3 gives remainder 0 and so are divisible by 418
1254/627 = 2 gives remainder 0 and so are divisible by 627
1254/1254 = 1 gives remainder 0 and so are divisible by 1254
Factors of 1257
1257/1 = 1257 gives remainder 0 and so are divisible by 1
1257/3 = 419 gives remainder 0 and so are divisible by 3
1257/419 = 3 gives remainder 0 and so are divisible by 419
1257/1257 = 1 gives remainder 0 and so are divisible by 1257
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