Math, asked by jmpjaga, 8 days ago

find hcf of 1254 using listing multiples

Answers

Answered by shkmaria2006
1

Answer:

Factors of 1254 =1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254

Distinct Factors of 1254 = 1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254,

Note: Factors of 1254 and Distinct factors are the same.

Factors of -1254 = -1, -2, -3, -6, -11, -19, -22, -33, -38, -57, -66, -114, -209, -418, -627, -1254,

What are the Factors of 1257

Factors of 1257 =1, 3, 419, 1257

Distinct Factors of 1257 = 1, 2, 3, 6, 11, 19, 22, 33, 38, 57, 66, 114, 209, 418, 627, 1254, 1, 3, 419, 1257,

Note: Factors of 1257 and Distinct factors are the same.

Factors of -1257 = -1, -2, -3, -6, -11, -19, -22, -33, -38, -57, -66, -114, -209, -418, -627, -1254, -1, -3, -419, -1257,

Negative factors are just factors with negative sign.The factors are numbers that can divide 1257 without remainder.

Every number is divisible by itself and 1.

Factors of 1254

1254/1 = 1254 gives remainder 0 and so are divisible by 1

1254/2 = 627 gives remainder 0 and so are divisible by 2

1254/3 = 418 gives remainder 0 and so are divisible by 3

1254/6 = 209 gives remainder 0 and so are divisible by 6

1254/11 = 114 gives remainder 0 and so are divisible by 11

1254/19 = 66 gives remainder 0 and so are divisible by 19

1254/22 = 57 gives remainder 0 and so are divisible by 22

1254/33 = 38 gives remainder 0 and so are divisible by 33

1254/38 = 33 gives remainder 0 and so are divisible by 38

1254/57 = 22 gives remainder 0 and so are divisible by 57

1254/66 = 19 gives remainder 0 and so are divisible by 66

1254/114 = 11 gives remainder 0 and so are divisible by 114

1254/209 = 6 gives remainder 0 and so are divisible by 209

1254/418 = 3 gives remainder 0 and so are divisible by 418

1254/627 = 2 gives remainder 0 and so are divisible by 627

1254/1254 = 1 gives remainder 0 and so are divisible by 1254

Factors of 1257

1257/1 = 1257 gives remainder 0 and so are divisible by 1

1257/3 = 419 gives remainder 0 and so are divisible by 3

1257/419 = 3 gives remainder 0 and so are divisible by 419

1257/1257 = 1 gives remainder 0 and so are divisible by 1257

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