Find HCF of 1260 and 1440 by Euclid's division lemma
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let a and b be two consecutive numbers
a=1440
b=1260
a<b
a/b
1440/1260
Euclid division algorithm as follows
1440=1260×1+180
1260=180×7+0
therefore,HCF=180
hope it helps
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Answer:
let a and b be two consecutive numbers
a=1440
b=1260
a<b
a/b
1440/1260
Euclid division algorithm as follows
1440=1260×1+180
1260=180×7+0
therefore,HCF=180
hope it helps
plZ Mark as brainliest
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