Question

find hcf of 13205,1365,1330 by Euclid's division lemma.

Answer 1

First calculate $\gcd(1365,1330)$ : 
$1365 = 1\times 1330 + 35 \\ 1330 = 38\times 35 + 0$

So $\gcd(1365, 1330) = 35$

Next find $\gcd(35, 13205)$ :
$13205=377\times 35+10 \\ 35 = 3\times 10+ 5\\10=2\times 5+0$

So  $\gcd(35, 13205) = 5$

 $\implies \\\gcd(13205,1365,1330) = \gcd(13205, \gcd(1365,1330)) = \gcd(13205,35) = 5$