Math, asked by AshvikaJamwal, 8 months ago

find HCF of 138, 180 and 260 by division method​

Answers

Answered by srinivasrampu33
3

Answer:

HCF of 138,180,260 is 2

using Euclid division lemma

180=138×1+42

138=42×3+12

42=12×3+6

12=6×2+0

here hcf is 6

next use the Euclid division lemma in the case of 260

260=6×43+2

6=2×3+0

:-therefore the hcf of 138,180 and 260 is 2

HCF=2

Answered by KanavDhingra
5

HCF of 138,180,260 is 2

using Euclid division lemma

180=138×1+42

138=42×3+12

42=12×3+6

12=6×2+0

here hcf is 6

next use the Euclid division lemma in the case of 260

260=6×43+2

6=2×3+0

:-therefore the hcf of 138,180 and 260 is 2

HCF=2

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