Math, asked by rashidulhoquemasjid, 8 months ago

Find HCF of 150, 3909, 702 by prime factorisation method​

Answers

Answered by vktripathi8810
1

Step-by-step explanation:

prime factorization of 150 = 2*3*5*5

prime factorization of 3909 = 3*1303

prime factorization of 702 = 2*3*3*3*13

Therefore HCF(150,3909,702) = 3

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Answered by vanshg28
0

Answer:

This is also correct.

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