find hcf of 180, 252 & 324 by euclids division lemma
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Answered by
1
by using Euclid division algorithm
324= 252×1+72
252=72×3+36
72=36×2+0
hcf=36
now considered 36 and 180
180=36×5+0
so hcf are 36
324= 252×1+72
252=72×3+36
72=36×2+0
hcf=36
now considered 36 and 180
180=36×5+0
so hcf are 36
Answered by
1
a = bq + r
324 = 252 × 1 + 72
252 = 72 × 3 + 36
72 = 36 × 2 + 0
HCF(324,252) = 36
180 = 36 × 5 + 0
HCF(36,180) = 36
HCF of 180,252 and 324 is 36
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